461. Hamming Distance - Easy

Posted fatttcat

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了461. Hamming Distance - Easy相关的知识,希望对你有一定的参考价值。

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:
0 ≤ xy < 231.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
       ↑   ↑

The above arrows point to positions where the corresponding bits are different.

 

bit manipulation

time = O(# of bits), space = O(1)

class Solution 
    public int hammingDistance(int x, int y) 
        int cnt = 0;
        for(int i = x ^ y; i != 0; i >>= 1) 
            cnt += i & 1;
        
        return cnt;
    

 

以上是关于461. Hamming Distance - Easy的主要内容,如果未能解决你的问题,请参考以下文章

461. Hamming Distance

461. Hamming Distance

461. Hamming Distance

461. Hamming Distance

leetcode No461. Hamming Distance

leetcode-461(Hamming Distance)