PAT 甲级 1027 Colors in Mars (20 分)（简单，进制转换）

Posted 2022-07-30 caiyishuai

1027 Colors in Mars (20 分)

 

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

 

题意：

三个数分别转十三进制

 

AC代码：

#include <iostream>
using namespace std;
int main()
    char ans[13];
    for(int i=0;i<10;i++) ans[i]=i+‘0‘;
    ans[10]=‘A‘,ans[11]=‘B‘,ans[12]=‘C‘;
    int a[3];
    for(int i=0;i<3;i++) cin>>a[i];
    cout<<"#";
    for(int i=0;i<3;i++)
        cout<<ans[a[i]/13]<<ans[a[i]%13];
    
    return 0;

#include<bits/stdc++.h>
using namespace std;
char d[15]=‘0‘,‘1‘,‘2‘,‘3‘,‘4‘,‘5‘,‘6‘,‘7‘,‘8‘,‘9‘,‘A‘,‘B‘,‘C‘;
int main()
    int a[5];
    cin>>a[1]>>a[2]>>a[3];
    cout<<"#";
    for(int i=1;i<=3;i++)
    
        int x=a[i];
        int b[5];
        int k=0;
        //转成13进制
        while(x>=13)
            b[++k] = x/13;
            x=x%13; 
        
        b[++k]=x;
        if(k==1)
            cout<<0<<d[b[1]];
        else
            cout<<d[b[1]]<<d[b[2]];
                 
    
    return 0;
 

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