requests实现文件下载, 期间显示文件信息&下载进度_python3

Posted 2022-07-17 xust14521

requests实现文件下载, 期间显示文件信息&下载进度

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"""使用模块线程方式实现网络资源的下载
# 实现文件下载, 期间显示文件信息&下载进度
# 控制台运行以显示进度
"""
import requests
import os.path as op
import os
from sys import stdout


def downloadfile(url, filename):
    """下载文件并显示过程
    :param url: 资源地址
    :param filename: 保存的名字, 保存在当前目录
    """
    # print(url)
    filename = filename + '.' + op.splitext(url)[-1]
    file_to_save = op.join(os.getcwd(), filename)
    # print(file_to_save)

    with open(file_to_save, "wb") as fw:
        with requests.get(url, stream=True) as r:
            # 此时只有响应头被下载
            # print(r.headers)
            print("下载文件基本信息:")
            print('-' * 30)
            print("文件名称:", filename)
            print("文件类型:", r.headers["Content-Type"])
            filesize = r.headers["Content-Length"]
            print("文件大小:", filesize, "bytes")
            print("下载地址:", url)
            print("保存路径:", file_to_save)
            print('-' * 30)
            print("开始下载")

            chunk_size = 128
            times = int(filesize) // chunk_size
            show = 1 / times
            show2 = 1 / times
            start = 1
            for chunk in r.iter_content(chunk_size):
                fw.write(chunk)
                if start <= times:
                    stdout.write(f"下载进度: show:.2%\r")
                    start += 1
                    show += show2
                else:
                    stdout.write("下载进度: 100%")
            print("\n结束下载")


if __name__ == "__main__":
    downloadfile("https://code.jquery.com/jquery-3.4.1.js", "a")

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