C#应用程序单例并激活程序的窗口 使其显示在最前端

Posted 2022-07-15 soundcode

 public class SoftHelper
    
        ///<summary>
        /// 该函数设置由不同线程产生的窗口的显示状态
        /// </summary>
        /// <param name="hWnd">窗口句柄</param>
        /// <param name="cmdShow">指定窗口如何显示。查看允许值列表，请查阅ShowWlndow函数的说明部分</param>
        /// <returns>如果函数原来可见，返回值为非零；如果函数原来被隐藏，返回值为零</returns>
        [DllImport("User32.dll")]
        private static extern bool ShowWindowAsync(IntPtr hWnd, int cmdShow);


        /// <summary>
        ///  该函数将创建指定窗口的线程设置到前台，并且激活该窗口。键盘输入转向该窗口，并为用户改各种可视的记号。
        ///  系统给创建前台窗口的线程分配的权限稍高于其他线程。 
        /// </summary>
        /// <param name="hWnd">将被激活并被调入前台的窗口句柄</param>
        /// <returns>如果窗口设入了前台，返回值为非零；如果窗口未被设入前台，返回值为零</returns>
        [DllImport("User32.dll")]
        private static extern bool SetForegroundWindow(IntPtr hWnd);



        private const int SW_SHOWNOMAL = 1;
        private static void HandleRunningInstance(Process instance)
        
            ShowWindowAsync(instance.MainWindowHandle, SW_SHOWNOMAL);//显示
            SetForegroundWindow(instance.MainWindowHandle);//当到最前端
        

        private static Process RuningInstance()
        
            Process currentProcess = Process.GetCurrentProcess();
            Process[] Processes = Process.GetProcessesByName(currentProcess.ProcessName);

            foreach (Process process in Processes)
            
                if (process.Id != currentProcess.Id)
                
                    return process;
                
            
       

            return null;
        

       /// <summary>
       /// 程序以单例运行 
       /// </summary>
       public static void SoftSingle<T>() where T:Form, new()
       
            Process process = RuningInstance();
            if(process==null)
            
                var mainForm = new T();
                Application.Run(mainForm);
            
            else
            
                HandleRunningInstance(process);
            
        


    

调用为：SoftHelper.SoftSingle<Main>();