PATA1028 List Sorting

Posted 2022-07-03 tsruixi

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤10
?5
?? ) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student‘s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID‘s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID‘s in increasing order.

Sample Input 1:
3 1
000007 James 85
000010 Amy 90
000001 Zoe 60
Sample Output 1:
000001 Zoe 60
000007 James 85
000010 Amy 90
Sample Input 2:
4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98
Sample Output 2:
000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60
Sample Input 3:
4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90
Sample Output 3:
000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

开始技术总结：

• 主要就是cmp函数的编写，可以通过编写三个cmp函数来分别对应于三种排序的情况，然后根据输入得到的C值来选择哪个cmp函数应用，我使用的是通过定义一个全局变量C，然后编写一个cmp函数，在cmp函数里面区别三种排序情况。注意如果要使用C来判断，必须把C定义为全局变量。这个函数的参考代码如下：

bool cmp(Student a, Student b) 
    if (C == 1) 
        return a.id < b.id;
    
    else if (C == 2) 
        if (strcmp(a.name, b.name) == 0) 
            return a.id < b.id;
        
        else 
            return strcmp(a.name, b.name) < 0;
        
        
    
    else if (C == 3) 
        if (a.grade == b.grade) 
            return a.id < b.id;
        
        else 
            return a.grade < b.grade;
        
    

所有部分的代码：

//在VS2017上编写，通过PAT测试满分25
#define _CRT_SECURE_NO_WARNINGS
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
using namespace std;

struct Student 
    int id;
    char name[10];
    int grade;
stu[100010];

int C;//全局变量用来在cmp函数使用，判定排序方式

bool cmp(Student a, Student b) 
    if (C == 1) 
        return a.id < b.id;
    
    else if (C == 2) 
        if (strcmp(a.name, b.name) == 0) 
            return a.id < b.id;
        
        else 
            return strcmp(a.name, b.name) < 0;
        
        
    
    else if (C == 3) 
        if (a.grade == b.grade) 
            return a.id < b.id;
        
        else 
            return a.grade < b.grade;
        
    

int main() 
    int N;//分别记录人数N
    scanf("%d%d", &N, &C);
    for (int i = 0; i < N; i++) 
        scanf("%d%s%d", &stu[i].id, stu[i].name, &stu[i].grade);
    
    sort(stu, stu + N, cmp);
    for (int i = 0; i < N; i++) 
        printf("%06d %s %d\n", stu[i].id, stu[i].name, stu[i].grade);
    

    system("pause");
    return 0;