整数对

Posted 2022-06-28 liulex

整数对

枚举余数

 

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

int main()

    int T;
    scanf("%d",&T);
    while(T--)
    ll n,m,p;
    scanf("%lld%lld%lld",&n,&m,&p);
    ll t=n/p;
    ll ans=0;
    for(ll r=0;r<=p-1;r++)
        if(r==0)
            ans+=t*m;
        else if(r<=n%p)
            ans+=(t+1)*(m/(p/__gcd(r,p)));
        
        else ans+=t*(m/(p/__gcd(r,p)));
    
        cout<<ans<<‘\n‘;