Android获取设备唯一码

Posted 2022-06-26 diyishijian

String uuid = "";
        String serial = null;

        String m_szDevIDShort = "35" +
                Build.BOARD.length() % 10 + Build.BRAND.length() % 10 +

                Build.CPU_ABI.length() % 10 + Build.DEVICE.length() % 10 +

                Build.DISPLAY.length() % 10 + Build.HOST.length() % 10 +

                Build.ID.length() % 10 + Build.MANUFACTURER.length() % 10 +

                Build.MODEL.length() % 10 + Build.PRODUCT.length() % 10 +

                Build.TAGS.length() % 10 + Build.TYPE.length() % 10 +

                Build.USER.length() % 10; //13 位

        try 
            serial = android.os.Build.class.getField("SERIAL").get(null).toString();
            //API>=9 使用serial号
            uuid = new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
         catch (Exception exception) 
            //serial需要一个初始化
            serial = "serial"; // 随便一个初始化
            //使用硬件信息拼凑出来的15位号码
            uuid = new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
        

转自：https://blog.csdn.net/u014031072/article/details/70257907