C#正则表达式根据分组命名取值

Posted 2022-06-22 jtclassroom

string[] regexList = new string[] 
                @"^(?<TickerPart1>[0-9A-Z])[ 0_]?(?<TickerPart2>[A-Z][0-9]) ?(COM(DTY)?|INDEX|IDX|IND|CURNCY|CUR|CLQ|ILQ|IDS)$",
                @"^(?<Ticker>[0-9A-Z]2,5[A-Z][0-9]) ?(COM(DTY)?|INDEX|IDX|IND|CURNCY|CUR)$",
                @"^(?<Ticker>[0-9A-Z]2,5[A-Z][0-9])$",
            ;
string externalId = "3ABZ9 COMDTY";
//测试例子
//A Z9 INDEX;AZ9 CUR;A_H9 IDX;A0H9COM;ABZ9 INDEX;3ABZ9 COMDTY;ABZ9;3ABZ9
foreach (string regexString in regexList)

    if (Regex.IsMatch(externalId, regexString, RegexOptions.IgnoreCase))
    
        Regex reg = new Regex(regexString, RegexOptions.IgnoreCase);
        Match mc = reg.Match(externalId);
        GroupCollection groups = mc.Groups;
        string convertid = "";
        foreach (string grn in reg.GetGroupNames())
        
            if (grn.Contains("Ticker"))
　　　　　　　　　 convertid += groups[grn].Value;
        
        Console.WriteLine(converted);
        break;
    

以上例子将正则表达式中所有已经命名了的分组提取出来