二元运算符重载

Posted 2022-06-20 wanghao-boke

以非成员函数方式重载运算符

/***
overtwo.cpp
***/
#include<iostream>
using namespace std;

class Box

    public:
        Box(double l = 2.0,double b = 2.0,double h = 2.0)
        
            length = l;
            breadth = b;
            height = h;
        
        double getVolume()
        
            return length*breadth*height;
        
    private:
        double length;
        double breadth;
        double height;
    friend Box operator+(const Box& a,const Box& b);
;

Box operator+(const Box& a,const Box& b)

    Box box;
    box.length = a.length+b.length;
    box.breadth = a.breadth+b.breadth;
    box.height = a.height + b.height;
    return box;


int main()

    Box box1(3.3,1.2,1.5);
    Box box2(8.5,6.0,2.0);
    Box box3;
    double volume = 0.0;

    volume = box1.getVolume();
    cout << "Volume of box1 : " << volume << endl;

    volume = box2.getVolume();
    cout << "Volume of box2 : " << volume << endl;

    box3 = box1 + box2;

    volume = box3.getVolume();
    cout << "Volume of box3 : " << volume << endl;

    return 0;

运算结果：

exbot@ubuntu:~/wangqinghe/C++/20190808$ g++ overtwo.cpp -o overtwo

exbot@ubuntu:~/wangqinghe/C++/20190808$ ./overtwo

Volume of box1 : 5.94

Volume of box2 : 102

Volume of box3 : 297.36

 

当两个对象相加时是没有顺序要求的，但是要重载+让其与一个数字相加有顺序要求，可以通过加一个友元函数使另一个顺序的输出合法。

/***
overfriend.cpp
***/
#include<iostream>
using namespace std;

class A

    private:
        int a;
    public:
        A();
        A(int n);
        A operator+(const A &obj);
        A operator+(const int b);
    friend A operator+(const int b,A obj);
        void display();
;

A::A()

    a = 0;


A::A(int n)

    a = n;


A A::operator +(const A& obj)  //重载+号，用于对象相加

    return this->a+obj.a;


A A::operator+(const int b) //对象和数相加

    return A(a+b);


A operator+ (const int b, A obj) // 友元函数调用第二个重载+的成员函数，相当于obj.operator(b)

    return obj+b;


void A::display()

    cout << a << endl;


int main()

    A a1(1);
    A a2(2);
    A a3,a4,a5;
    a1.display();
    a2.display();
    int m = 1;
    a3 = a1 + a2; //可以调换顺序，相当于a3=a1.operator+(a2);
    a3.display();

    a4 = a1 + m; //加了一个友元函数可调换顺序
    a4.display();

    a5 = m + a1;
    a5.display();

    return 0;

运算结果：

exbot@ubuntu:~/wangqinghe/C++/20190808$ ./overfrined

1

2

3

2

2