java 多线程-资源共享

Posted 2022-06-14

单继承具有局限性，推荐使用Runnable接口，启动线程必须借用Thread类对象

• new Thread(Run,String s).start() ,new Thread()可以传字符串
• Thread.currentThread().getName();当前线程的名字，即传入的字符串
• 重写的run()方法没有返回值，且不能抛出异常
• Thread.sleep(200)；暂停该线程200毫秒延迟，1000毫秒约等于一秒

模拟抢票：

public class ThreadDownload implements Runnable 

private int num=99;
public void run()

    while(true)
    
        if(num<0)
        
            break;
        
        try 
            Thread.sleep(200);
         catch (InterruptedException e) 
            // TODO Auto-generated catch block
            e.printStackTrace();
          //模拟延迟，停止200毫秒
        System.out.println(Thread.currentThread().getName()+"-"+num--);
    


public static void main(String[]args)
   //一份资源
    ThreadDownload web=new ThreadDownload();
    System.out.println(Thread.currentThread().getName());//在main线程中，打印main
    //多个代理
    new Thread(web,"a").start();
    new Thread(web,"b").start();
    new Thread(web,"c").start();

模拟龟兔赛跑:

public class ThreadDownload implements Runnable 
private String winner;
public void run()


    for(int step=1;step<=100;step++)
    
        if(Thread.currentThread().getName().equals("兔子")&&step%10==0)
        
            try 
                Thread.sleep(100);  
             catch (InterruptedException e) 
                // TODO Auto-generated catch block
                e.printStackTrace();
            
        
        System.out.println(Thread.currentThread().getName()+"-->"+step);
        boolean flag=gameOver(step);
        if(flag)
        
            break;
        
    

private boolean gameOver(int step)

    if(winner!=null)
    
        return true;
    else
    
        if(step==100)
        
            winner=Thread.currentThread().getName();
            System.out.println("winner=="+winner);
            return true;
        
    

    return false;

public static void main(String[]args)
   //一份资源
     ThreadDownload td=new ThreadDownload();
    new Thread(td,"乌龟").start();
    new Thread(td,"兔子").start();