二叉树的创建遍历删除求高度

Posted 2022-05-29 feliz

创建> 需要给定一个root的key，所有小于这个key的放到左边，大于key的放到右边， 比如vector<int> tree = 5,2,7,1,9,3,8,最后的树：

           5
          /          2   7
        /\   /       1  3  8 9

实现：

TreeNode* AddNode(int key, int direction, TreeNode* root)
 
     if(direction == 0)//左孩子
     
         if(root->leftChild == NULL)//找到对应的叶节点插入
             root->leftChild = new binaryTreeNode<T>(key);
         
         else
             root->leftChild = AddNode(key, direction, root->leftChild);
         
     
     else//右孩子
     
         if (root->rightChild == NULL) //找到相应的叶节点插入
             root->rightChild = new binaryTreeNode<T>(key);
         
         else
             root->rightChild = AddNode(key, direction, root->rightChild);
         
     
     
     return root;

//vector[0]作为root
TreeNode* createTree(vector<int>& tree)
      int nodes = tree.length();
      int pos = 0;
      if(nodes<1) return NULL;
      TreeNode* root = new TreeNode(tree[pos++]);

      while(pos < nodes)
            if(tree[pos]<tree[0])
                  root->left = AddNode(tree[pos++], 0, root);
            else
                  root->right = AddNode(tree[pos++], 1, root);
      
      return root;