集合练习：根据学院英文名找到学员对象

Posted 2022-05-20 dean-0

包装学生类：

/**
 * @author Administrator
 *    学生类
 */
public class Students 
    private String name;
    private char sex;
    public String getName() 
        return name;
    
    public void setName(String name) 
        this.name = name;
    
    public char getSex() 
        return sex;
    
    public void setSex(char sex) 
        this.sex = sex;
    
    public Students(String name, char sex) 
        super();
        this.name = name;
        this.sex = sex;
    

学生类

测试类：

 1 import java.util.Collections;
 2 import java.util.HashMap;
 3 import java.util.Iterator;
 4 import java.util.Map;
 5 import java.util.Scanner;
 6 import java.util.Set;
 7 
 8 public class Text01 
 9     static Scanner input= new Scanner(System.in);
10     public static void main(String[] args) 
11         Map<String, Students> student = new HashMap<String, Students>();
12         student.put("Jack0", new Students("张三", ‘男‘));
13         student.put("Jack1", new Students("李四", ‘女‘));
14         student.put("Jack2", new Students("王五", ‘男‘));
15         student.put("Jack3", new Students("赵六", ‘女‘));
16         student.put("Jack4", new Students("钱七", ‘男‘));
17         
18         Set<String> keys = student.keySet();
19         //遍历方法一:增强型for循环
20         for(String st:keys) 
21             Students value = student.get(st);
22             System.out.println(st+"---"+value.getName()+"---"+value.getSex());
23         
24         
25             
26         System.out.println("*****************************************");
27         //遍历方法二：迭代器Iterator
28             Iterator<String> it = keys.iterator();
29             while(it.hasNext()) 
30                 String key1 = it.next();
31                 Students value1 = student.get(key1);
32                 System.out.println(key1+"---"+value1.getName()+"---"+value1.getSex());
33         
34             
35         //遍历方法三：键值对获取
36             System.out.println("*****************************************");
37             for(Map.Entry<String, Students> map:student.entrySet()) 
38                 String key = map.getKey();
39                 Students stu = map.getValue();
40                 System.out.println(key+"---"+stu.getName()+"---"+stu.getSex());
41             
42             
43             
44         System.out.println("您输入您要找的学员的英文名：");
45         String name = input.next();
46         if(student.containsKey(name)) 
47             Students stu = student.get(name);
48             System.out.println("您要找的英文名是"+name+"的学员中文名是："+stu.getName()+"    性别为："+stu.getSex());
49         else 
50             System.out.println("很抱歉，没有英文名是"+name+"的学员。");
51         
52     
53 

测试类

运行测试结果：