Java 采用泛型 实现通过学员英文名查找学员对应信息

Posted 2022-05-20 twuxian

|--需求说明

|--实现思路

1、创建学员类，用于初始化信息

2、采用map储存数据，key储存学员的英文名，value储存学员的其他信息

3、通过判断map中有没有用户输入的英文名来判断是否给出学员信息

 

|--代码内容

 1 package kehou;
 2 
 3 /**
 4  * @auther:：9527
 5  * @Description: 学生类
 6  * @program: gaoJiTeXing
 7  * @create: 2019-07-27 10:36
 8  */
 9 public class Student 
10     private String ename;   //英文名
11     private String cname;  //中文名
12     private int id;        //员工工号
13     private String gender;   //性别
14 
15     public Student() 
16     
17 
18     public Student(String ename, String cname, int id, String gender) 
19         this.ename = ename;
20         this.cname = cname;
21         this.id = id;
22         this.gender = gender;
23     
24 
25     public String getEname() 
26         return ename;
27     
28 
29     public void setEname(String ename) 
30         this.ename = ename;
31     
32 
33     public String getCname() 
34         return cname;
35     
36 
37     public void setCname(String cname) 
38         this.cname = cname;
39     
40 
41     public int getId() 
42         return id;
43     
44 
45     public void setId(int id) 
46         this.id = id;
47     
48 
49     public String getGender() 
50         return gender;
51     
52 
53     public void setGender(String gender) 
54         this.gender = gender;
55     
56 

学员类---初始化基础信息

 1 package kehou;
 2 
 3 import java.util.HashMap;
 4 import java.util.Scanner;
 5 
 6 /**
 7  * @auther:：9527
 8  * @Description: 程序入口
 9  * @program: gaoJiTeXing
10  * @create: 2019-07-27 10:45
11  */
12 public class StudentTest 
13     static Scanner scanner = new Scanner(System.in);
14     public static void main(String[] args) 
15         //String eName, String cName, int id
16         Student st1 = new Student("Jack","李霖",58,"男");
17         Student st2 = new Student("Jone","郑书豪",25,"男");
18         Student st3 = new Student("Tom","黎明",32,"女");
19         Student st4 = new Student("Evan","李明丽",8,"女");
20 
21         //创建map集合
22         HashMap<String,Student> map = new HashMap<>();
23         map.put(st1.getEname(),st1);
24         map.put(st2.getEname(),st2);
25         map.put(st3.getEname(),st3);
26         map.put(st4.getEname(),st4);
27 
28        //接受用户信息
29         System.out.println("请输入学员英文名");
30         String ename = scanner.next();
31 
32         //根据用户输入的信息进行查找
33         if (map.containsKey(ename))
34             System.out.println("姓名是："+map.get(ename).getCname()+"\\t性别是："+map.get(ename).getGender());
35         else 
36             System.out.println("没有你要找的人");
37         
38     
39 

程序入口

 

 

|--运行结果