JS 获取URL 后面的参数

Posted 2022-05-18 imtudou

function GetRequest() 
            var url = location.search; //获取url中"?"符后的字串   
            var theRequest = new Object();
            if (url.indexOf("?") != -1) 
                var str = url.substr(1);
                strs = str.split("&");
                for (var i = 0; i < strs.length; i++) 
                    theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
                
            

            if (theRequest == undefined || theRequest == null) 
                theRequest == "";
            

            return theRequest;
         
        
        
        
        
        
        
        
        
        
        
        
        //解决中文乱码
         function getParam(name) 
                var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)");
                var r = window.location.search.substr(1).match(reg);
                if (r != null)
                        return decodeURI(r[2]);   //对参数进行decodeURI解码
                return null;
           
        
        
        
        https://localhost:5001/script/selectbox/template/tableItem.html?nos%20=JT201600723&date=2016-10&company=母公司&curreny=人民币(CNY)&status=已审计&wd=实际
        
        
        
        %20  为空格  传参的时候注意点即可