将十六进制的颜色字符串转为UIColor
Posted 思微随想
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扩展UIColor,将十六进制的颜色字符串转成UIColor对象。
extension UIColor { static func colorWithHexString(hex:String) -> UIColor { var cString:String = hex.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).uppercaseString if cString.hasPrefix("#") { let index:String.CharacterView.Index = cString.startIndex.advancedBy(1) cString = cString.substringFromIndex(index) } if cString.characters.count != 6 { return UIColor.grayColor() } //按两位分割字符内容 let rString = cString.substringToIndex(cString.startIndex.advancedBy(2)) let gString = cString.substringFromIndex(cString.startIndex.advancedBy(2)).substringToIndex(cString.startIndex.advancedBy(2)) let bString = cString.substringFromIndex(cString.startIndex.advancedBy(4)).substringToIndex(cString.startIndex.advancedBy(2)) var r:CUnsignedInt = 0, g:CUnsignedInt = 0, b:CUnsignedInt = 0 NSScanner(string: rString).scanHexInt(&r) NSScanner(string: gString).scanHexInt(&g) NSScanner(string: bString).scanHexInt(&b) return UIColor(red: CGFloat(r) / 255.0 , green: CGFloat(g) / 255.0, blue: CGFloat(b) / 255.0, alpha: 1) } }
现在就可以调用了,
self.view.backgroundColor = UIColor.colorWithHexString("#ffff00")
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