Relative Sort Array

Posted 2022-04-29 overlows

Relative Sort Array

Given two arrays arr1 and arr2, the elements of arr2 are distinct, and all elements in arr2 are also in arr1.

Sort the elements of arr1 such that the relative ordering of items in arr1 are the same as in arr2.  Elements that don't appear in arr2 should be placed at the end of arr1 in ascending order.

Example 1:

Input: arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6]
Output: [2,2,2,1,4,3,3,9,6,7,19]

Constraints:

arr1.length, arr2.length <= 1000
0 <= arr1[i], arr2[i] <= 1000
Each arr2[i] is distinct.
Each arr2[i] is in arr1.

Code

//
//  main.cpp
//  按照字符串2对字符串1进行排序
//
//  Created by mac on 2019/7/20.
//  Copyright ? 2019 mac. All rights reserved.
//

#include <iostream>
#include <vector>
#include <algorithm>


using namespace std;

class Solution 
public:
    vector<int> relativeSortArray(vector<int>& arr1, vector<int>& arr2) 
        vector<int> arr3,arr4;
        for (int i=0;i<arr2.size() ; ++i) 
            for (int j=0; j<arr1.size(); ++j) 
                if (arr1[j]==arr2[i]) 
                    arr3.push_back(arr2[i]);
                    arr1[j]=1001;
                
            
        
        vector<int>::iterator it=arr1.begin();
        while (it!=arr1.end()) 
            if (*it!=1001) 
                arr4.push_back(*it);
            
            it++;
        
        sort(arr4.begin(), arr4.end());
        for (int j=0; j<arr4.size(); ++j) 
            arr3.push_back(arr4[j]);
        
        return arr3;
    
;


int main(int argc, const char * argv[]) 
    // insert code here...
    vector<int> arr1,arr2,arr;
    arr1=2,3,1,3,2,4,6,7,9,2,19;
    arr2=2,1,4,3,9,6;
    Solution so;
    arr=so.relativeSortArray(arr1, arr2);
    for (int i=0; i<arr.size(); ++i) 
        cout<<arr[i]<<" ";
    
    
    cout<<endl;
//    [2,3,1,3,2,4,6,7,9,2,19]
//    [2,1,4,3,9,6]

    
    return 0;

运行结果

2 2 2 1 4 3 3 9 6 7 19 
Program ended with exit code: 0

参考文献

• https://leetcode.com/problems/relative-sort-array/