7kyu (难度系数kyu阶段数值越大难度越低) 数组分组及求和

Posted 2022-04-22 ukzq

https://www.codewars.com/kata/row-weights/train/java

public class Solution

    public static int[] rowWeights (final int[] weights)
    
        int result1 = 0;
        int result2 = 0;
        int len = weights.length;
        if(len==0)
          return new int[]0, 0; // Do your magic!
        
        for(int i=0;i<len;i++)
          if(i%2==0)
            result1+=weights[i];
          else
            result2+=weights[i];
          
        
        return new int[]result1,result2;
        
    

大神的Solution

public class Solution 
  public static int[] rowWeights (final int[] weights) 
    int totals[] = new int[2], idx = 0;
    for (int w : weights) totals[(idx++)%2] += w;
    return totals;
  
  

 

js的解:

function rowWeights(array)
  //your code here
    let a = 0;
    let b = 0;
    for (let i=0;i<array.length;i++) 
      if (i % 2 == 0) 
        a += array[i];
       else 
        b += array[i];
      
    
    return new Array(a, b);
    

js大神的Solution

function rowWeights(array)
  let t1 = array.filter((x, i)=>i%2==0).reduce((a,item)=>a+item,0);
  let t2 = array.filter((x, i)=>i%2!=0).reduce((a,item)=>a+item,0);
  
  return [t1, t2]

rowWeights=arr=>arr.reduce((a,b,i)=>(a[i%2]+=b,a),[0,0])

function rowWeights(array)
  var arr = [0, 0];
  for (var i = 0; i < array.length; i++) 
    i % 2 == 0 ? arr[0] += array[i] : arr[1] += array[i];
  
  return arr;

const rowWeights = arr => arr.reduce((a, w, i) => (a[i%2]+=w, a), [0, 0]);

const rowWeights = a => a.reduce(([s1,s2],n,i)=> i%2 ? [s1,s2+n]: [s1+n, s2] , [0,0])

function rowWeights(array) 
  return array.reduce((t, x, i) => 
    t[i % 2] += x;
    return t;
  , [0, 0]);

function rowWeights(array) 
  return array.reduce((a, b, i) => (a[i%2] += b, a), [0, 0]);

function rowWeights(a,f=0,s=0)
  return (a.map((x,i)=>i%2?s+=x:f+=x),[f,s]);