对比多层字典是否相同函数

Posted 2022-04-21 xiaokuangnvhai

 

现有2个字典且是多层级的，找出2个字典的不同且输出，实现如下：

ok_req=
    "version": "9.0.0",
    "is_test": True,
    "store": "",
    "urs": "",
    "device": 
        "os": "android",
        "imei": "99001062198893",
        "device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
        "mac": "02:00:00:00:00:00",
        "galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
        "udid": "a34b1f67dd5797df93fdd8b072f1fb8110fd0db6",
        "network_status": "wifi"
    ,
    "adunit": 
        "category": "VIDEO",
        "location": "1",
        "app": "7A16FBB6",
        "blacklist": ""
    ,
    "ext_param":
        "is_start" : 0,
        "vId":"VW0BRMTEV"
    

not_ok=
    "version": "9.0.0",
    "is_test": True,
    "urs": "",
    "store": "",
    "device": 
        "os": "android",
        "imei": "99001062298893",
        "device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
        "mac": "02:00:00:00:00:00",
        "galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
        "udid": "a34b1f67dd5797da93fdd8b072f1fb8110fd0db6",
        "network_status": "wifi"
    ,
    "adunit": 
        "category": "VIDEO",
        "location": "1",
        "app": "7A16FBB6",
        "blacklist": ""
    ,"ext_param": 
        "is_start": 0,
        "vid": "VW0BRMTEV"
    

#对比多层字典函数
def dic_compare(dic_name,compar_dic):
    for key, value in dic_name.items():  #遍历字典
        if key not in compar_dic.keys(): #如果KEY不在对比的字典中，输出字典
            print(key, value)
        if type(value) != dict: #如果value不是多层
            if value not in compar_dic.values(): #不是多层的，如果value和对比字典不一致输出
                print(key, value)
        if  type(value) == dict: #如果value是多层的，那么通过递归再次走上面代码进行对比
            dic_compare(value,compar_dic[key])

dic_compare(ok_req,not_ok) #调用函数