java 读取xml

Posted 2022-04-16 hglsv

采用sax的方式来读取并解析xml文件。

public static void main(String[] args) throws DocumentException 
		//1.获取到读取对象
		SAXReader saxReader = new SAXReader();
		Document doc = saxReader.read("f:\\info.xml");
		Element rootElement = doc.getRootElement();
		getNodes(rootElement);
	
	static public void getNodes(Element rootElement)
		String name = rootElement.getName();
		System.out.println("节点名称:"+name);
		//获取节点属性
		List<Attribute> attributes = rootElement.attributes();
		for (Attribute attribute : attributes) 
			System.out.println("属性名称:"+attribute.getName()+",属性value"+attribute.getValue());
		
		String value=rootElement.getTextTrim();
		if(!value.equals(""))
			System.out.println("节点value"+value);
		
		//判断是否有下一个节点
		Iterator<Element> elementIterator = rootElement.elementIterator();
		while (elementIterator.hasNext()) 
			Element next = elementIterator.next();
			getNodes(next);