Django2.0异常：Specifying a namespace in include() without providing an app_name is not supported.

Posted 2022-04-13 bruce-blogs

Django2.0异常：Specifying a namespace in include() without providing an app_name is not supported.

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Django2.0异常：Specifying a namespace in include() without providing an app_name is not supported.编辑器

在CRM项目权限分配管理中
用django设置好了URL后报错。URL代码为

from django.conf.urls import url,include
from django.contrib import admin

urlpatterns = [
    url(r‘^admin/‘, admin.site.urls),
    url(r‘^rbac/‘, include(‘rbac.urls‘,namespace=‘rbac‘)),
    url(r‘^‘, include(‘web.urls‘)),
]

源码为

def include(arg, namespace=None):
    app_name = None
    if isinstance(arg, tuple):
        # Callable returning a namespace hint.
        try:
            urlconf_module, app_name = arg
        except ValueError:
            if namespace:
                raise ImproperlyConfigured(
                    ‘Cannot override the namespace for a dynamic module that ‘
                    ‘provides a namespace.‘
                )
            raise ImproperlyConfigured(
                ‘Passing a %d-tuple to include() is not supported. Pass a ‘
                ‘2-tuple containing the list of patterns and app_name, and ‘
                ‘provide the namespace argument to include() instead.‘ % len(arg)
            )
    else:
        # No namespace hint - use manually provided namespace.
        urlconf_module = arg
 
    if isinstance(urlconf_module, str):
        urlconf_module = import_module(urlconf_module)
    patterns = getattr(urlconf_module, ‘urlpatterns‘, urlconf_module)
    app_name = getattr(urlconf_module, ‘app_name‘, app_name)
    if namespace and not app_name:
        raise ImproperlyConfigured(
            ‘Specifying a namespace in include() without providing an app_name ‘
            ‘is not supported. Set the app_name attribute in the included ‘
            ‘module, or pass a 2-tuple containing the list of patterns and ‘
            ‘app_name instead.‘,
        )
    namespace = namespace or app_name
    # Make sure the patterns can be iterated through (without this, some
    # testcases will break).
    if isinstance(patterns, (list, tuple)):
        for url_pattern in patterns:
            pattern = getattr(url_pattern, ‘pattern‘, None)
            if isinstance(pattern, LocalePrefixPattern):
                raise ImproperlyConfigured(
                    ‘Using i18n_patterns in an included URLconf is not allowed.‘
                )
    return (urlconf_module, app_name, namespace)

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作者：masserd
来源：CSDN
原文：https://blog.csdn.net/zoulonglong/article/details/79612973
版权声明：本文为博主原创文章，转载请附上博文链接！

从include()函数可以看出来，这个函数有两个参数，一个arg，一个namespace，我在代码中也是两个参数，但是异常中提示了，没有提供app_name,还提示需要传入一个两元元组，从第六行代码,可以看出来，arg就是那个元组，且给app_name赋值了

urlconf_module, app_name = arg

经过一番面向百度debug,修改后代码为

from django.conf.urls import url,include
from django.contrib import admin

urlpatterns = [
    url(r‘^admin/‘, admin.site.urls),
    url(r‘^rbac/‘, include((‘rbac.urls‘,‘rbac‘),namespace=‘rbac‘)),
    url(r‘^‘, include(‘web.urls‘)),
]

成功解决问题