用封装实现错误的赋值而导致输出的信息不符合实际

Posted 2022-04-04 zeng1997

package Month.JUL.JUL11;

import java.util.Scanner;

public class QiEr 
    private String name;
    private int xingBie;
    private int health;
    private int love;

    public String getName() 
        return name;
    

    public void setName(String name) 
        this.name = name;
    

    public int getXingBie() 
        return xingBie;
    

    public void setXingBie(int xingBie) 
        if (xingBie == 1 || xingBie == 2) 
            this.xingBie = xingBie;
         else 
            System.out.println("您选择的性别不在该范围内！");
            this.xingBie = 1;
        
    

    static Scanner input = new Scanner(System.in);

    public int getHealth() 
        return health;
    

    public void setHealth(int health) 
        if (health > 0 && health < 100) 
            this.health = health;
         else 
            this.health = 60;
            System.out.println("输出信息错误，默认使用初始值！");
        
    

    public int getLove() 
        return love;
    

    public void setLove(int love) 
        if (love > 0 && love < 100) 
            this.love = love;
         else 
            this.love = 60;
            System.out.println("输出信息错误，默认使用初始值！");
        
    

    public static void main(String[] args) 
        QiEr qi = new QiEr();
        System.out.println("请输入企鹅名称：");
        qi.setName(input.next());
        System.out.println("请选择企鹅性别(1、Q仔，2、Q妹)：");
        qi.setXingBie(input.nextInt());
        String xingBie = "";
        if (qi.getXingBie() == 1) 
            xingBie = "Q仔";
         else 
            xingBie = "Q妹";
        
        System.out.println("请输入健康值：");
        qi.setHealth(input.nextInt());
        System.out.println("请输入亲密度：");
        qi.setLove(input.nextInt());

        System.out
                .println("企鹅名称：" + qi.getName() + ",性别：" + xingBie + ",健康值：" + qi.getHealth() + "亲密度：" + qi.getLove());