707 设计链表
Posted cznczai
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了707 设计链表相关的知识,希望对你有一定的参考价值。
class ListNode
int val;
ListNode next;
ListNode (int val) this.val = val;
class MyLinkedList
/** Initialize your data structure here. */
ListNode head = null;
public MyLinkedList()
head = new ListNode(0);
/** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */
public int get(int index)
ListNode cur = head.next;
int num = -1;
while(cur != null)
num ++;
if(num == index)
return cur.val;
cur = cur.next;
return -1;
/** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */
public void addAtHead(int val)
ListNode node = new ListNode(val);
node.next = head.next;
head.next = node;
/** Append a node of value val to the last element of the linked list. */
public void addAtTail(int val)
ListNode cur = head;
while(cur.next != null)
cur = cur.next;
cur.next = new ListNode(val);
/** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */
public void addAtIndex(int index, int val)
ListNode cur = head;
int num = -1;
while(cur != null)
num ++;
if(num == index )
ListNode node = new ListNode(val);
node.next = cur.next;
cur.next = node;
cur = cur.next;
/** Delete the index-th node in the linked list, if the index is valid. */
public void deleteAtIndex(int index)
ListNode cur = head;
int num = -1;
while(cur.next != null)
num ++;
if(num == index )
ListNode temp = cur.next;
cur.next = temp.next;
break;
cur = cur.next;
/**
* Your MyLinkedList object will be instantiated and called as such:
* MyLinkedList obj = new MyLinkedList();
* int param_1 = obj.get(index);
* obj.addAtHead(val);
* obj.addAtTail(val);
* obj.addAtIndex(index,val);
* obj.deleteAtIndex(index);
*/
以上是关于707 设计链表的主要内容,如果未能解决你的问题,请参考以下文章