JSON字符串的生成

Posted 2020-07-28 Nicolasap

　 public class Corporation 
    {
　　　　 public string remark { get; set; }
        public string version { get; set; }
        public string @operator { get; set; } 
    }

  public class TenderDoc
    {
        public string tenderdocid { get; set; }
        public Corporation corporation { get; set; }
        public string context { get; set; }public string @operator { get; set; }
    }

 public class Root
    {
        public List<TenderDoc> datas { get; set; }
        public string flag{ get; set; }
    }

这样就定义了json的实体类。

　　　　　　　Corporation cop = new Corporation();
            cop.remark = "remark";
            cop.version = "C#";
            [email protected] = "niap";

            List<TenderDoc> listtd = new List<TenderDoc>();
            for (int i = 0; i < 2; i++)
            {
                TenderDoc td = new TenderDoc();
                td.tenderdocid = "NO1";
                td.corporation = cop;
                td.context = "context";
                [email protected] = "miap";
                listtd.Add(td);
            }
            Root root = new Root() { datas = listtd, flag = "001" };
            string jsonStr = JsonConvert.SerializeObject(root);
            Response.Write(jsonStr);

最后调用 JsonConvert.SerializeObject()，就可以将实体类对象转为JSON。

转换结果如下

{
    "datas": [
        {
            "tenderdocid": "NO1",
            "corporation": {
                "remark": "remark",
                "version": "C#",
                "operator": "niap"
            },
            "context": "context",
            "operator": "miap"
        },
        {
            "tenderdocid": "NO1",
            "corporation": {
                "remark": "remark",
                "version": "C#",
                "operator": "niap"
            },
            "context": "context",
            "operator": "miap"
        }
    ],
    "flag": "001"
}