一本通 1615：例 1序列的第 k 个数

Posted 2022-03-09 benjamin-cpp

序列的第k个数

快速幂

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Code:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;
//Mystery_Sky
//
#define Mod 200907
#define M 10001000
#define ll long long
int n, k, a[M];

ll quickPow(ll x, ll k)

    ll ret = 1;
    while(k) 
        if(k & 1) ret = (ret * x) % Mod;
        k >>= 1;
        x = (x * x) % Mod;
    
    return ret % Mod;

int t;

int main() 
    scanf("%d", &t);
    while(t--) 
        ll a, b, c, k;
        scanf("%lld%lld%lld%lld", &a, &b, &c, &k);
        if((a + c) == (2 * b)) 
            ll d = (b - a) % Mod;
            printf("%lld\n", (a + ((k - 1) * d) % Mod) % Mod);
        
        else 
            ll q = (b / a) % Mod;
            printf("%lld\n", (a % Mod * quickPow(q, k-1)) % Mod);
        
    
    return 0;