Swagger使用--在一个Controller中使用相同(类似)参数的方法

Posted 2022-02-26 ttonly

解决方法：在Startup.cs中加入CustomSchemaIds

 // Register the Swagger generator, defining 1 or more Swagger documents
 services.AddSwaggerGen(c =>

        c.SwaggerDoc("v1", new Info  Title = "CompareAPI", Version = "v1" );
        c.CustomSchemaIds((type) => type.FullName);//根据全名来生成
);

控制器代码类似：

    [Route("api/[controller]")]
    [ApiController]
    public class AccountController : ControllerBase
    
        [HttpPost]
        [Route("Register")]
        public async Task<ActionResult<T>> Register(RegisterModel registerModel)
        
        
        [HttpPost]
        [Route("ResetPassword")]
        public async Task<ActionResult<T>> ResetPassword(ResetPasswordModel resetPasswordModel)
        
        
    

https://github.com/domaindrivendev/Swashbuckle.AspNetCore/blob/master/README.md#customize-schema-ids