python 根据时间戳获取秒🐱

Posted 2022-02-18 sea-stream

 

print("当前时间： ",time.strftime(‘%Y.%m.%d %H:%M:%S ‘,time.localtime(time.time())))


import time
import datetime
t = time.time()
print (t)                       #原始时间数据
print (int(t))                  #秒级时间戳
print (int(round(t * 1000)))    #毫秒级时间戳
nowTime = lambda:int(round(t * 1000))
print (nowTime());              #毫秒级时间戳，基于lambda
print (datetime.datetime.now().strftime(‘%Y-%m-%d %H:%M:%S‘))   #日期格式化
#输出
1499825149.26
1499825149
1499825149257
1499825149257
2017-07-12 10:05:49


#将日期转为秒级时间戳
dt = ‘2018-01-01 10:40:30‘
ts = int(time.mktime(time.strptime(dt, "%Y-%m-%d %H:%M:%S")))
print (ts)
#输出
1514774430


#将秒级时间戳转为日期
ts = 1515774430
dt = time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(ts))
print(dt)
#输出
2018-01-13 00:27:10

参考：
https://www.cnblogs.com/fangbei/p/python-time.html