Leetcode[154]-Find Minimum in Rotated Sorted Array II
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Link: https://leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/
Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
The array may contain duplicates.
C++:
方法一:直接遍历求解
class Solution {
public:
int findMin(vector<int>& nums) {
int n = nums.size();
int min = nums[0];
for(int i = 1; i < n; i++) {
if(nums[i]<min){
min = nums[i];
}
}
return min;
}
};
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