三种离散化
Posted tieway59
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了三种离散化相关的知识,希望对你有一定的参考价值。
等有空再测试
```cpp
#define debug(x) cerr<<#x<<" = "<<x<<endl
#include <bits/stdc++.h>
using namespace std;
const int maxn = 3e5 + 5;
const int inf = 0x3f3f3f3f;
int n = 10, m, ans;
int a[] = {1, 55, 777, 5, 89, 433, 242, 55555555, 242, 777};
vector<int> hush(a, a + n);
int b[10], c[10];
void initHush1() {
sort(hush.begin(), hush.end());
auto it = unique(hush.begin(), hush.end());
hush.resize(distance(hush.begin(), it));
}
inline int getId1(int x) {
return distance(hush.begin(), lower_bound(hush.begin(), hush.end(), x));
}
void initHush2() {
for (int i = 0; i < n; ++i) {
b[i] = a[i];
}
sort(b, b + n);
m = unique(b, b + n) - b;
}
inline int getId2(int x) {
return lower_bound(b, b + m, x) - b;
}
struct Node {
int val, pos;
bool operator<(const Node &T) const {
if (val == T.val)return pos < T.pos;
return val < T.val;
}
} V[10];
void initHush3() {
for (int i = 0; i < n; ++i) {
V[i].val = a[i];
V[i].pos = i;
}
sort(V, V + n);
for (int i = 1, j = 0; i < n; i++) {
if (i == 1 || V[i].val != V[i - 1].val)j++;
c[V[i].pos] = j;
}
}
int getId3(int pos){
return c[pos];
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
initHush1();
initHush2();
initHush3();
debug(getId1(1));
debug(getId1(55555));
debug(getId2(1));
debug(getId2(55555));
debug(getId3(1));
debug(getId3(5));
return 0;
}
/*
8 5
1 4
3 6
4 5
4 6
4 7
*/
```
以上是关于三种离散化的主要内容,如果未能解决你的问题,请参考以下文章