N12-数值的整次方

Posted 2021-12-01 kexiblog

题目描述

给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方。

package new_offer;
/**
 * 给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方
 * @author Sonya
 *
 */
public class N12_Power {
	
	public double Power(double base, int exponent) {
		double power=1.0;
		if(exponent==0) return 1;
			
			for(int i=0;i<Math.abs(exponent);i++) {
				power=power*base;
			}
			if(exponent<0)return 1/power;
			return power;
	  }

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		N12_Power n12=new N12_Power();
		System.out.println(n12.Power(3, 5));
		System.out.println(n12.Power(2, -3));
	}

}