Python hangman小游戏
Posted noonjuan
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Python hangman小游戏相关的知识,希望对你有一定的参考价值。
hangman
# words.py 使用pickle永久性存储数据 import pickle filename = ‘words.pk‘ data = [‘cat‘, ‘dog‘, ‘perro‘, ‘gato‘, ‘horse‘, ‘elephant‘, ‘mono‘] with open(filename, ‘wb‘) as f: pickle.dump(data, f)
# hangman.py 猜词游戏 # 使用pickle导入数据 import pickle # 使用random.choice函数在序列中随机选择 import random def hangman(word): # 传入一个参数(word) # 错误数量 wrong = 0 # 要画的步骤 stages = ["", "______ ", "| | ", "| | ", "| 0 ", "| /|\ ", "| / \ ", "| ", ] # 将词转换为一个列表 rletters = list(word) # 生成一个下划线的待猜列表 board = ["_"] * len(word) # 未赢 win = False print(‘Welcome to Hangman‘) # 如果画还没画完 while wrong < len(stages) - 1: print(‘\n‘) # 猜一个字母 msg = ‘Guess a letter: ‘ char = input(msg) # 如果字母在列表中 if char in rletters: # 将列表中的字母剔除(‘$‘),并在待猜列表中添加字母 cind = rletters.index(char) board[cind] = char rletters[cind] = ‘$‘ # 如果字母不在列表中 else: # 错误+1 wrong += 1 # 显示待猜列表 print(‘word: ‘ + (" ".join(board))) # 打印图画 e = wrong + 1 print(‘\n‘.join(stages[0:e])) # 如果待猜列表中以及没有下划线了,赢了 if ‘_‘ not in board: print(‘You win!‘) print(‘ ‘.join(board)) win = True break # 如果输了 if not win: print(‘You lose! It was {}‘.format(word)) def random_word(filename=‘words.pk‘): with open(filename, ‘rb‘) as f: data = pickle.load(f) return random.choice(data) if __name__ == ‘__main__‘: while True: hangman(random_word()) flag = input(‘Do you want to continue?(Y/N) ‘) if flag.lower() not in [‘y‘, ‘yes‘]: break
以上是关于Python hangman小游戏的主要内容,如果未能解决你的问题,请参考以下文章
如果值不改变 Hangman Javascript,如何跳过“if”语句