类型断言的最佳实践

Posted 2021-11-28 swei

Golang语言中的类型断言的最佳实践

• 利用函数typejudge 来判断传入的实参是什么类型，并打印出它的类型及数值

package main
import(
    "fmt"
    _"sort"
    _"math/rand"
)
type Wisdom struct{
	name string
}

func TypeJuDge (Items... interface{}) {
	for index, value := range Items {
		switch value.(type){
			case bool:
				fmt.Printf("第%v个参数是布尔类型，它的值是%v \\n",index+1,value)
			case string:
				fmt.Printf("第%v个参数是字符串类型，它的值是%v \\n",index+1,value)
			case int,int32,int64:
				fmt.Printf("第%v个参数是整数类型，它的值是%v \\n",index+1,value)
			case float32,float64:
				fmt.Printf("第%v个参数是浮点类型，它的值是%v \\n",index+1,value)
			// case bool:
			// 	fmt.Printf("第%v个参数是bool类型，它的值是%v \\n",index+1,value)
			case Wisdom:
				fmt.Printf("第%v个参数是自定义Wisdom类型，它的值是%v \\n",index+1,value)
			case *Wisdom:
				fmt.Printf("第%v个参数是自定义Wisdom指针类型，它的值是%v \\n",index+1,value)
			}
	}
}

func main(){
	wisdom := Wisdom{ "智慧"}
	wisdom2 := &Wisdom{ "人名"}
	var n1 float64 = 68.9
	var n2 bool 
	var n3 int = 100
	var name string = "GOLANG"
	TypeJuDge(wisdom,wisdom2,n1,n2,n3,name) 

}

• 　终端显示结果：

GOLANG语言的运行报错

• duplicate case bool in type switch previous case at .\\main.go:14:4
• 原因是因为我多写了一个case bool 判断，报类型重复情况