深度优先搜索(DFS)(Java)

Posted 2021-11-27 huayra

 1 //1 使用邻接表 时间复杂度: O(n+e)
 2 //递归
 3 public void DFS(int v)
 4 {
 5     System.out.print(this.vexs[v].data + " ");
 6     this.visited[v] = true;
 7         
 8     for(ArcNode p = this.vexs[v].firstarc; p != null; p = p.nextarc)
 9         if(this.visited[p.adjvex] == false)
10             this.DFS(p.adjvex);
11 }
12 
13 //迭代(借助栈)
14 public void DFS(int v)
15 {
16     System.out.print(this.vexs[v].data + " ");
17     this.visited[v] = true;
18     Stack stack = new Stack();
19     stack.push(vexs[v]);
20     
21     for(int i = 0; i < this.vexs.length; i++)
22         this.vexs[i].next = this.vexs[i].firstarc;
23     
24     while(!stack.isEmpty())
25     {
26         VexNode q = stack.getTop();
27         ArcNode p;
28         for(p = q.next; p != null && this.visited[p.adjvex] == true; p = p.nextarc);
29         if(p != null)
30         {
31             System.out.print(this.vexs[p.adjvex].data + " ");
32             this.visited[p.adjvex] = true;
33             stack.push(this.vexs[p.adjvex]);
34             q.next = p.nextarc;
35         }
36         else
37             stack.pop();
38     }
39 }

 

 1 //使用邻接矩阵 时间复杂度: O(n^2)
 2 //递归
 3 public void DFS(int v)  
 4 {
 5     System.out.print(this.vexs[v] + " ");
 6     this.visited[v] = true;
 7     
 8     for(int i = 0; i < this.vexnum; i++)
 9         if(this.adjacencyMatrix[v][i] == 1 && this.visited[i] == false)
10             this.DFS(i);
11 }
12 
13 //迭代(借助栈)
14 public void DFS(int v)
15 {
16     System.out.print(this.vexs[v] + " ");
17     this.visited[v] = true;
18     Stack stack = new Stack();
19     stack.push(v);
20     
21     while(!stack.isEmpty())
22     {
23         v = stack.getTop();
24         int i;
25         for(i = 0; i < this.vexnum; i++)
26             if(this.adjacencyMatrix[v][i] == 1 && this.visited[i] == false)
27             {
28                 System.out.print(this.vexs[i] + " ");
29                 this.visited[i] = true;
30                 stack.push(i);
31                 break;
32             }
33         if(i == this.vexnum)
34             stack.pop();
35     }
36 }