扑克牌算法

Posted 2021-11-26 mianyang0902

核心步骤：利用随机数给数组赋值。

 1 public class wicket_2 {
 2     public static void main(String[] args) {
 3         String []s=new String[]{"黑桃","红桃","梅花","方块"};
 4         String []sign=new String[]{"A","2","3","4","5","6","7","8","9","10","J","Q","K"};
 5         final int N=52;
 6         int card[]=new int[N];
 7         for(int i=0;i<card.length;i++) {
 8             card[i]+=i;
 9         }
10         System.out.println("开始时牌顺序：");
11         for(int i=0;i<card.length;i++) {
12             System.out.printf("  %s%s",s[card[i]/13],sign[card[i]%13]);
13             if((i+1)%13==0) {
14                 System.out.println();
15             }
16         }
17         //模拟洗牌
18         for(int i=0;i<card.length;i++) {
19             card[i]=(int)((Math.random())*52);
20         }
21         System.out.println("洗牌后的顺序为：");
22         for(int i=0;i<card.length;i++) {
23             System.out.printf("  %s%s",s[card[i]/13],sign[card[i]%13]);
24             if((i+1)%13==0) {
25                 System.out.println();
26             }
27         }
28     }
29 }

运算结果：