1017 A除以B (20 分)

Posted 2021-11-26 hk456

#include <iostream>
#include <string>
using namespace std;
int main() {
    string num;
    int a, b, m;   
    cin >> num >> m;    // 一个为字符串一个为整形数字避免了麻烦的处理
    int len = num.size();
    a = (num[0] - ‘0‘) / m;
    b = (num[0] - ‘0‘) % m;
    if (len == 1 || (len > 1 && a != 0))   // 判断数字的第一个是否为零，位数为1的情况，不为1的情况
        cout << a;
    for (int i = 1; i < len; i++) {
        a = (b * 10 + (num[i] - ‘0‘)) / m;
        cout << a;
        b = (b * 10 + (num[i] - ‘0‘)) % m;
    }
    cout << " " << b;
    return 0;
}