js获取url查询字符串参数

Posted 2021-11-25 qqfontofweb

最近看js高级程序设计

对其中查询字符串参数的获得重新写了，当传递一个完整的URL的时候对查询字符串的提取

function getQueryArgs(){
    var qs = (location.search.length > 0 ? location.search.substr(1) : ‘‘),
        //保存每一项
        args = {},
        //得到每一项
        items = qs.length ? qs.split(‘&‘) : [],
        item = null,
        name = null,
        value = null,
        i = 0,
        len = items.length;

        for(i = 0;i<len ;i++){
            item = items[i].split(‘=‘),
            name = decodeURIComponent(item[0])
            value = decodeURIComponent(item[1])
            if(name.length){
                args[name] = value;
            }
        }
        return args;
}
getQueryArgs()

function getQueryArgs(url){
    var qs = (url.length > 0 ? url.substring(url.indexOf(‘?‘)).substr(1) : ‘‘),
        //保存每一项
        args = {},
        //得到每一项
        items = qs.length ? qs.split(‘&‘) : [],
        item = null,
        name = null,
        value = null,
        i = 0,
        len = items.length;

        for(i = 0;i<len ;i++){
            item = items[i].split(‘=‘),
            name = decodeURIComponent(item[0])
            value = decodeURIComponent(item[1])
            if(name.length){
                args[name] = value;
            }
        }
        return args;
}