python super()继承和多继承

Posted 2021-11-22 plusultra

class A:
    def __init__(self):
        self.n = 2

    def add(self, m):
        print('self is {} @A.add'.format(self))
        self.n += m


class B(A):
    def __init__(self):
        self.n = 3

    def add(self, m):
        print('self is {} @B.add'.format(self))
        super().add(m)
        self.n += 3


class C(A):
    def __init__(self):
        self.n = 4

    def add(self, m):
        print('self is {} @C.add'.format(self))
        super().add(m)
        self.n += 4


class D(B, C):
    def __init__(self):
        self.n = 5

    def add(self, m):
        print('self is {} @D.add'.format(self))
        super().add(m)
        self.n += 5
d = D()
d.add(2)        #虽然使用的时父类的add(),但是self一直是代表D类的self.
print(d.n)

多继承的顺序是先从左到右，再从下到上。
# d.n=5+3+4+2+5=19                    
输出结果：
# self is <__main__.D object at 0x10d99e4e0> @D.add
# self is <__main__.D object at 0x10d99e4e0> @B.add
# self is <__main__.D object at 0x10d99e4e0> @C.add
# self is <__main__.D object at 0x10d99e4e0> @A.add
19