poj1106
Posted mxang
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极角排序扫一圈。
今天没什么状态写个水题减轻负罪感(大雾)
1 #include <cstdio> 2 #include <cmath> 3 #include <cstring> 4 #include <algorithm> 5 #include <vector> 6 using namespace std; 7 typedef double db; 8 const db eps = 1e-6; 9 const db pi = acos(-1); 10 int sign(db k){ 11 if (k>eps) return 1; else if (k<-eps) return -1; return 0; 12 } 13 int cmp(db k1,db k2){return sign(k1-k2);} 14 struct point{ 15 db x,y,ang; 16 point operator + (const point &k1) const{return (point){k1.x+x,k1.y+y};} 17 point operator - (const point &k1) const{return (point){x-k1.x,y-k1.y};} 18 point operator * (db k1) const{return (point){x*k1,y*k1};} 19 point operator / (db k1) const{return (point){x/k1,y/k1};} 20 int operator == (const point &k1) const{return cmp(x,k1.x)==0&&cmp(y,k1.y)==0;} 21 db abs(){ return sqrt(x*x+y*y);} 22 db dis(point k1){return ((*this)-k1).abs();} 23 db getw(){return atan2(y,x);} 24 }; 25 struct circle{ 26 point o;db r; 27 int inside(point k){return cmp(r,o.dis(k))>=0;} 28 }c; 29 vector<point> v; 30 bool cmp2(point a,point b){ 31 return a.ang<b.ang; 32 } 33 int n;point t; 34 int main(){ 35 while (scanf("%lf%lf%lf",&c.o.x,&c.o.y,&c.r)&&c.r>0){ 36 //scanf("%lf%lf%lf",&c.o.x,&c.o.y,&c.r); 37 scanf("%d",&n); 38 while (n--){ 39 scanf("%lf%lf",&t.x,&t.y); 40 if(c.inside(t)){ 41 t.ang = (c.o-t).getw(); 42 v.push_back(t); 43 v.push_back({t.x,t.y,t.ang+2*pi}); 44 } 45 } 46 sort(v.begin(),v.end(),cmp2); 47 int m = v.size()/2; 48 int ans = 0; 49 for(int l=0,r=0;l<m;l++){ 50 while (r<2*m&&v[r].ang-v[l].ang<=pi) 51 r++; 52 ans=max(ans,r-l); 53 } 54 printf("%d\n",ans); 55 v.clear(); 56 } 57 }
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