leetcode [216]Combination Sum III
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Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Note:
- All numbers will be positive integers.
- The solution set must not contain duplicate combinations.
Example 1:
Input: k = 3, n = 7 Output: [[1,2,4]]
Example 2:
Input: k = 3, n = 9 Output: [[1,2,6], [1,3,5], [2,3,4]]
题目大意:
给定1到9这九个数字,从中选取k个数字,使得这k个数字之和等于n。这k个数字的选择不能重复。
解法:
采用dfs做:
java:
class Solution { List<List<Integer>>res; private void dfs(int k,int n,int index,List<Integer>tmpSum){ if(n<0) return; if(k==0){ if(n==0) res.add(new ArrayList<>(tmpSum)); return; } for(int i=index;i<10;i++){ tmpSum.add(i); dfs(k-1,n-i,i+1,tmpSum); tmpSum.remove(tmpSum.size()-1); } } public List<List<Integer>> combinationSum3(int k, int n) { res=new ArrayList(); List<Integer>tmpSum=new ArrayList<>(); dfs(k,n,1,tmpSum); return res; } }
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