矩阵链乘最优化实现
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矩阵链乘最优化算法(括号化算法),关键要找到A[i]...A[j]矩阵链相乘做最少乘法次数(存在m[][]中)的相乘顺序,记录在矩阵s[][]中。再利用递归定义矩阵链乘算法。递归的出口是只有一个矩阵(直接返回)或者两个矩阵(返回相乘后的结果矩阵)的情况。
1 //#include"OptimalMatrixMultiplication.h" 2 #include<iostream.h> 3 #include<stdio.h> 4 #include<stdlib.h> 5 #include<memory.h> 6 #include<fstream.h> 7 8 //using namespace std; 9 10 #define N 6 //N Matrices 11 #define MAX 15 // Biggest number of elements in row/column of matrices 12 typedef long (*Mat)[MAX]; ////////////!!! define a 2dim array pointer 13 int num; 14 Mat pp[N]; // To store the result matrix of any two matrices\' multiplication 15 long A[N+1][MAX][MAX]; // store matrices to be calculated, A[0] is not used !!! 16 17 //find m[][] and s[][] 18 void Matrix_Chain_Order(int *p,int m[N+1][N+1],int s[N+1][N+1]) 19 { 20 for (int i=1;i<=N;i++) 21 { 22 m[i][i] = 0; 23 } 24 for(int L=2;L<=N;L++) 25 { 26 for(i=1;i<=N-L+1;i++) 27 { 28 int j = i+L-1; 29 m[i][j] = (1<<30); ////m[i][j] can\'t be bigger than 2^31-1 !!! 30 for(int k=i;k<j;k++) /// There is no " ^ " symbol in C/C++ language !!! 31 { //////////// pow(x,y) -> x^y 32 int q = m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]; 33 if(q<m[i][j]) 34 { 35 m[i][j] = q; 36 s[i][j] = k; 37 } 38 } 39 } 40 } 41 42 } 43 44 //print the multiplication order 45 void Print_OptimalParens(int s[N+1][N+1],int i,int j) 46 { 47 if(i == j) 48 { 49 cout<<"A"<<i; 50 } 51 else 52 { 53 cout<<"("; 54 Print_OptimalParens(s,i,s[i][j]); 55 Print_OptimalParens(s,s[i][j]+1,j); 56 cout<<")"; 57 } 58 } 59 60 // To generate matrices, all matrices have "the same" size 61 void Init_Matrix(long A[][MAX][MAX],int *p) 62 { 63 //read metrix data from file "MetrixData" generated by rand(); 64 ifstream fin("MetrixData.txt"); 65 //vector<int> vec; 66 long idata; 67 fin>>idata; 68 for(int i=1;i<=N;i++) 69 { 70 for(int j=0;j<p[i-1];j++) //matrices have different size! 71 { 72 for(int k=0;k<p[i];k++) 73 { 74 A[i][j][k] = idata; 75 fin>>idata; 76 } 77 } 78 } 79 } 80 81 Mat Matrix_Multiplication(Mat a,Mat b,Mat c) 82 { 83 for(int i=0;i<MAX;i++) 84 { 85 for(int j=0;j<MAX;j++) 86 { 87 for(int k=0;k<MAX;k++) 88 { 89 c[i][j]+=a[i][k]*b[k][j]; 90 } 91 } 92 } 93 return c; 94 } 95 96 Mat Matrix_Chain_Multiplication(int i,int j,int s[N+1][N+1]) 97 { 98 if(i == j) 99 { 100 return A[i]; 101 } 102 else if(i+1 == j) 103 { 104 pp[num] = (Mat)malloc(MAX*MAX*sizeof(long)); 105 if(pp[num] == NULL) 106 { 107 cout<<"Can\'t allocate memory!"; 108 exit(1); 109 } 110 memset(pp[num],0,MAX*MAX*sizeof(long)); 111 return Matrix_Multiplication(A[i],A[j],pp[num ++]); 112 // num ++; // This line can\'t be excuted !!! 113 } 114 else 115 { 116 Mat l_Mat = Matrix_Chain_Multiplication(i,s[i][j],s); 117 Mat r_Mat = Matrix_Chain_Multiplication(s[i][j]+1,j,s); 118 119 pp[num] = (Mat)malloc(MAX*MAX*sizeof(long)); 120 if(pp[num] == NULL) 121 { 122 cout<<"Can\'t allocate memory!"; 123 exit(1); 124 } 125 memset(pp[num],0,MAX*MAX*sizeof(long)); 126 127 return Matrix_Multiplication(l_Mat,r_Mat,pp[num ++]); 128 } 129 } 130 131 //print 2_Dim array 132 void Print_Array(long b[][MAX]) 133 { 134 for(int i=0;i<MAX;i++) 135 { 136 for(int j=0;j<MAX;j++) 137 { 138 cout<<b[i][j]<<" "; 139 } 140 cout<<endl; 141 } 142 } 143 144 void main() 145 { 146 int m[N+1][N+1]; 147 int s[N+1][N+1]; 148 int p[N+1]={10,8,5,7,6,12,9}; //store the size of matrices 149 Matrix_Chain_Order(p,m,s); 150 151 // print m[][] 152 for(int i=1;i<=N;i++) 153 { 154 for(int j=i+1;j<=N;j++) 155 { 156 cout<<" m["<<i<<"]["<<j<<"]: "<<m[i][j]; 157 } 158 cout<<endl; 159 } 160 //print s[][] 161 for(i=1;i<=N;i++) 162 { 163 for(int j=i+1;j<=N;j++) 164 { 165 cout<<" s["<<i<<"]["<<j<<"]: "<<s[i][j]; 166 } 167 cout<<endl; 168 } 169 170 Print_OptimalParens(s,1,6); 171 cout<<endl; 172 173 Init_Matrix(A,p); 174 //Print_Array(A[1]); 175 Matrix_Chain_Multiplication(1,6,s); 176 Print_Array(pp[--num]); 177 178 for(i=0;i<=num;i++) 179 { 180 free(pp[i]); 181 } 182 183 }
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