Majority Element

Posted 2020-07-25 dylqt

Majority Element 

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. 

You may assume that the array is non-empty and the majority element always exist in the array. 

 

每找出两个不同的element，则

成对删除。最终剩下的一定就是所求的。 可扩展到⌊ n/k ⌋的情况，每k个不同的element进行成对删除。

int majorityElement(int* nums, int numsSize) {

int times = 1;

int target = nums[0];

for(int i = 1; i < numsSize; i++)

{

if(target == nums[i])

times++;

else

{

times--;

if(times == 0)

{

target = nums[++i];

times = 1;

}

}

}

return target;

}