CF #edu 11 C. Hard Process
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题目链接:http://codeforces.com/problemset/problem/660/C
大意是给一个01数组,至多可以将k个0变为1,问最后数组中最长能有多少个连续的1,并输出。
问题转化一下就是找一个区间,使得区间中0的个数不多于k,且区间长度尽可能地长。尺取法做一下就可以了。
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.StringTokenizer; import java.io.IOException; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.InputStream; public class Main { public static void main(String[] args) { InputStream inputStream = System.in; OutputStream outputStream = System.out; InputReader in = new InputReader(inputStream); PrintWriter out = new PrintWriter(outputStream); Task solver = new Task(); solver.solve(1, in, out); out.close(); } static class Task { public void solve(int testNumber, InputReader in, PrintWriter out) { int n = in.nextInt(), k = in.nextInt(); int[] a = new int[n]; int l = 0; int cnt = 0; int ret = 0; int L = -1, R = -1; for (int r = 0; r < n; r++) { a[r] = in.nextInt(); cnt += 1 - a[r]; while (cnt > k) { cnt -= 1 - a[l++]; } if (r - l + 1 >= ret) { ret = r - l + 1; L = l; R = r; } } out.println(ret); for (int i = 0; i < n; i++) { if (L <= i && i <= R) { out.print(1); } else { out.print(a[i]); } out.print(" "); } } } static class InputReader { private BufferedReader reader; private StringTokenizer tokenizer; public InputReader(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream)); tokenizer = null; } public String next() { while (tokenizer == null || !tokenizer.hasMoreTokens()) { try { tokenizer = new StringTokenizer(reader.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } } }
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