写一个函数，随机生成N条不重复的手机号

Posted 2021-01-24 维也纳729

方法一：
import random
def phone(count):
    results = []
    while len(results)!=count:
        starts = [138,156,130,170,188,189]
        start = random.choice(starts)
        end = random.randint(0,99999999)
        res = ‘%s%08d\n‘%(start,end)            # 格式化字符串。%08d,获取8位的数字，并换行
        if res not in results:          # 循环遍历列表，不在列表中，就添加对应的号码到列表
            results.append(res)
    with open(‘phone.txt‘,‘w‘) as fw:
        fw.writelines(results)
phone(100)

 

方式二：

import random
import string

def email(count):
    if count<1:
        print(‘count不能小于1‘)
        return
    emails = set()
    while len(emails)!=count:
        email_len = random.randint(6,12)
        email_end = (‘@163.com‘, ‘@qq.com‘, ‘@sina.com‘, ‘@126.com‘)
        start = random.choice(string.ascii_uppercase)+        random.choice(string.ascii_lowercase)        + random.choice(string.digits)+random.choice(string.punctuation)
        other_len  = email_len - 4 #剩余字符串的长度
        other = random.sample(string.digits+string.ascii_letters+string.punctuation,other_len)
        res = other + list(start)
        random.shuffle(res)
        end = random.choice(email_end)
        email = ‘‘.join(res)+end+‘\n‘
        emails.add(email)
    with open(‘email.txt‘,‘w‘) as fw:
        fw.writelines(emails)