给出字符串分别计算出字符串中数字大小写字母的个数。（两种方法 getBytes( ) charAt( ) ）

Posted 2021-01-22 晴天x

public class LetterAndNumberCount {
    public static void main(String[] args) {
        Count("FJJgjsgfsd543632");
        count1("SFsefgdg2354354fsdf");
    }
    public static void Count(String str){
        int A = 0;
        int a = 0;
        int Number = 0;
        byte[] bytes = str.getBytes();  // 将字符串转为byte数组
        for(int i=0;i<bytes.length;i++){
            if(bytes[i] >= ‘a‘ && bytes[i] <= ‘z‘){
                a++;
            }else if(bytes[i]>=‘A‘ && bytes[i]<=‘Z‘){
                A++;
            }else if(bytes[i]>=‘0‘ && bytes[i]<=‘9‘){
                Number++;
            }
        }
        System.out.println("大写字母个数为："+ A);
        System.out.println("小写字母个数为："+ a);
        System.out.println("数字个数为："+ Number);
    }
    
    public static void count1(String str){
        int A = 0;
        int a = 0;
        int Number = 0;
        for(int i=0;i<str.length();i++){
            char array  = str.charAt(i); //便利数组后用charAt(i)来返回指定字符然后if进行判断
            if(array >= ‘a‘ && array <= ‘z‘){
                a++;
            }else if(array>=‘A‘ && array<=‘Z‘){
                A++;
            }else if(array>=‘0‘ && array<=‘9‘){
                Number++;
            }
        }
        System.out.println("大写字母个数为："+ A);
        System.out.println("小写字母个数为："+ a);
        System.out.println("数字个数为："+ Number);
        }
}