一般图极大团个数,最大团顶点数
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极大团个数:POJ 2989
#include <cstdio> #include <cstring> using namespace std; const int maxn = 130; bool mp[maxn][maxn]; int some[maxn][maxn], none[maxn][maxn], all[maxn][maxn]; int n, m, ans; void dfs(int d, int an, int sn, int nn) { if(!sn && !nn) ++ans; int u = some[d][0]; for(int i = 0; i < sn; ++i) { int v = some[d][i]; if(mp[u][v]) continue; for(int j = 0; j < an; ++j) all[d+1][j] = all[d][j]; all[d+1][an] = v; int tsn = 0, tnn = 0; for(int j = 0; j < sn; ++j) if(mp[v][some[d][j]]) some[d+1][tsn++] = some[d][j]; for(int j = 0; j < nn; ++j) if(mp[v][none[d][j]]) none[d+1][tnn++] = none[d][j]; dfs(d+1, an+1, tsn, tnn); some[d][i] = 0, none[d][nn++] = v; } } int work() { ans = 0; for(int i = 0; i < n; ++i) some[1][i] = i+1; dfs(1, 0, n, 0); return ans; } int main() { while(~scanf("%d %d", &n, &m)) { memset(mp, 0, sizeof mp); for(int i = 1; i <= m; ++i) { int u, v; scanf("%d %d", &u, &v); mp[u][v] = mp[v][u] = 1; } int tmp = work(); printf("%d ", tmp); } return 0; }
最大团顶点数:ZOJ 1492
#include <bits/stdc++.h> using namespace std; const int maxn = 55; bool mp[maxn][maxn]; int best, n, num[maxn]; bool dfs(int *adj, int total, int cnt) { int t[maxn], k; if (total == 0) { if (cnt > best) { best = cnt; return true; //剪枝4 } return false; } for (int i = 0; i < total; ++i) { if (cnt + total - i <= best) { return false; //剪枝1 } if (cnt + num[adj[i]] <= best) { return false; //剪枝3 } k = 0; for (int j = i + 1; j < total; ++j) if (mp[adj[i]][adj[j]]) { t[k++] = adj[j]; } //扫描与u相连的顶点中与当前要选中的adj[i]相连的顶点adj[j]并存储到数组t[]中,数量为k if (dfs(t, k, cnt + 1)) { return true; } } return false; } int MaximumClique() { int adj[maxn], k; best = 0; for (int i = n; i >= 1; --i) { k = 0; for (int j = i + 1; j <= n; ++j) if (mp[i][j]) { adj[k++] = j; } //得到当前点i的所有相邻点存入adj dfs(adj, k, 1); //每次dfs相当于必选当前i点看是否能更新best num[i] = best; } return best; } int main() { while (scanf("%d", &n) != -1 && n) { for (int i = 1; i <= n; ++i) for (int j = 1; j <= n; ++j) { scanf("%d", &mp[i][j]); } printf("%d ", MaximumClique()); } return 0; }
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