java 线程练习题1

Posted 2020-07-20 风起，唯有努力生存

随便选择两个城市作为预选旅游目标。实现两个独立的线程分别显示10次城市名，每次显示后休眠一段随机时间(1000ms以内)，哪个先显示完毕，就决定去哪个城市。分别用Runnable接口和Thread类实现。

package com.hanqi.xiancheng;

import java.util.Random;

public class Test6 implements Runnable {

    Random r = new Random();
    int a = r.nextInt(1000);

    @Override
    public void run() {

        for (int i = 0; i < 10; i++)

        {
            System.out.println(Thread.currentThread().getName());

            try {
                Thread.sleep(a);
            } catch (InterruptedException e) {
                // TODO 自动生成的 catch 块
                e.printStackTrace();
            }
        }

    }

}

package com.hanqi.xiancheng;

import java.util.Random;

public class Test8 extends Thread {

    Random r = new Random();
    int a = r.nextInt(1000);

    @Override
    public void run() {

        for (int i = 0; i < 10; i++)

        {
            System.out.println(Thread.currentThread().getName());

            try {
                Thread.sleep(a);
            } catch (InterruptedException e) {
                // TODO 自动生成的 catch 块
                e.printStackTrace();
            }
        }
    }

}

package com.hanqi.xiancheng;

public class Test7 {

    public static void main(String[] args) {
        // TODO 自动生成的方法存根
        Thread th=new Thread(new Test6());
        th.setName("海南");
        th.start();
        Thread th2=new Thread(new Test6());
        th2.setName("西藏");
        th2.start();

    }
    

}

package com.hanqi.xiancheng;

public class Test7 {

    public static void main(String[] args) {
        // TODO 自动生成的方法存根

        Test8 th3=new Test8();
        th3.setName("海南");
        th3.start();
        Test8 th4=new Test8();
        th4.setName("西藏");
        th4.start();
    }
    

}