poj 2386 Lake Counting(dfs)
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Lake Counting
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 28220 | Accepted: 14160 |
Description
Due to recent rains, water has pooled in various places in Farmer John‘s field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water (‘W‘) or dry land (‘.‘). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.
Given a diagram of Farmer John‘s field, determine how many ponds he has.
Given a diagram of Farmer John‘s field, determine how many ponds he has.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: M characters per line representing one row of Farmer John‘s field. Each character is either ‘W‘ or ‘.‘. The characters do not have spaces between them.
* Lines 2..N+1: M characters per line representing one row of Farmer John‘s field. Each character is either ‘W‘ or ‘.‘. The characters do not have spaces between them.
Output
* Line 1: The number of ponds in Farmer John‘s field.
Sample Input
10 12 W........WW. .WWW.....WWW ....WW...WW. .........WW. .........W.. ..W......W.. .W.W.....WW. W.W.W.....W. .W.W......W. ..W.......W.
Sample Output
3
Hint
OUTPUT DETAILS:
There are three ponds: one in the upper left, one in the lower left,and one along the right side.
There are three ponds: one in the upper left, one in the lower left,and one along the right side.
Java AC 代码
import java.util.Scanner; public class Main { static String field[][]; static int rows; static int columns; static int ponds; static boolean marked[][]; static int dx[] = {-1, 0, 1, -1, 1, -1, 0, 1}; static int dy[] = {1, 1, 1, 0, 0, -1, -1, -1}; public static void main(String[] args) { Scanner sc = new Scanner(System.in); rows = sc.nextInt(); columns = sc.nextInt(); field = new String[rows][columns]; marked = new boolean[rows][columns]; for(int i = 0; i < rows; i++) { String line = sc.next(); for(int j = 0; j < columns; j++) { field[i][j] = line.substring(j, j + 1); } } for(int i = 0; i < rows; i++) for(int j = 0; j < columns; j++) { if(!marked[i][j] && field[i][j].equals("W")) { dfs(i, j); ponds++; } } System.out.println(ponds); } public static void dfs(int row, int col) { for(int i = 0; i < 8; i++) { int _row = row + dy[i]; int _col = col + dx[i]; if(_row < rows && _row >= 0 && _col < columns && _col >= 0 && !marked[_row][_col] && field[_row][_col].equals("W")) { marked[_row][_col] = true; dfs(_row, _col); } } } }
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