快速输入输出模板
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高精类模板
基础实现凭借nofind
功能
高精类正整数加减乘除。
高精类正整数与普通正整数类型加减乘除。(只是运算时转成高精并没有单独写所以复杂度不优)
函数及默认参数
LEN 压位高精的模数
BASE_LEN 压位高精位数
LEN 数位长度
a 数组
len 长度
print()输出
del_zero()清除前导零
add()高精除法提前进位使用
opd()返回奇偶性
GNUM()构造函数,支持默认构造,传入数组、字符串、整形进行构造
~GNUM()析构函数
operator+加法
operator-减法
operator*乘法
operator/除法
operator<大小比较
operator<<输出流
operator>>输入流
class GNUM
{
private:
static const int BASE = 10000;
static const int BASE_LEN = 4;
static const int LEN = 101;
int a[LEN];
int len;
public:
GNUM()
{
len = 0;
memset(a, 0, sizeof(a));
}
~GNUM()
{
len = 0;
memset(a, 0, sizeof(a));
}
template <typename T>
GNUM(T x)
{
len = 0;
memset(a, 0, sizeof(a));
if (x == 0)
{
a[++len] = x;
return;
}
while (x)
{
a[++len] = x % BASE;
x /= BASE;
}
}
template <typename Y>
GNUM(Y *s, int lenth)
{
len = lenth;
memcpy(a, s, sizeof(a));
}
GNUM(char *x)
{
len = 1;
register int lenth = strlen(x) - 1;
memset(a, 0, sizeof(a));
for (register int i = lenth, j = 1; i >= 0; --i)
{
if (j == BASE)
j = 1, ++len;
a[len] += (x[i] - '0') * j;
j *= 10;
}
}
friend istream &operator>>(istream &input, GNUM &in)
{
char s[LEN];
input >> s;
in = GNUM(s);
return input;
}
friend ostream &operator<<(ostream &output, GNUM out)
{
output << out.a[out.len];
for (register int i = out.len - 1; i; --i)
{
output << right << setw(BASE_LEN) <<
setfill('0') << out.a[i];
}
return output;
}
inline void print()
{
printf("%d", a[len]);
for (register int i = len - 1; i; --i)
printf("%04d", a[i]);
}
inline void del_zero()
{
while (!a[len] && len > 1)
--len;
return;
}
inline void add(int k)
{
if (!k && len == 1 && !a[1])
return;
for (register int i = len; i; --i)
a[i + 1] = a[i];
a[1] = k;
++len;
}
inline friend bool operator<(const GNUM &x, const GNUM &y)
{
if (x.len == y.len)
{
register int i;
for (i = x.len; x.a[i] == y.a[i] && i > 1; --i)
;
if (i >= 1)
return x.a[i] < y.a[i];
else
return false;
}
else
return x.len < y.len;
}
inline friend bool operator>(const GNUM &x, const GNUM &y)
{
if (x.len == y.len)
{
register int i;
for (i = x.len; x.a[i] == y.a[i] && i > 1; --i)
;
if (i >= 1)
return x.a[i] > y.a[i];
else
return false;
}
else
return x.len > y.len;
return false;
}
inline friend bool operator==(GNUM x, GNUM y)
{
if (x.len == y.len)
{
register int i;
for (i = x.len; x.a[i] == y.a[i] && i >= 1; --i)
;
if (i >= 1)
return false;
return true;
}
else
return false;
return false;
}
inline friend bool operator<=(const GNUM &x, const GNUM &y)
{
return !(x > y);
}
inline friend bool operator>=(const GNUM &x, const GNUM &y)
{
return !(x < y);
}
template <typename AF>
inline friend GNUM operator+(const GNUM &x, const AF &y)
{
return x + GNUM(y);
}
inline friend GNUM operator+(const GNUM &x, const GNUM &y)
{
GNUM res;
res.len = max(x.len, y.len);
int k = 0;
for (register int i = 1; i <= res.len; ++i)
{
res.a[i] = x.a[i] + y.a[i] + k;
k = res.a[i] / BASE;
res.a[i] %= BASE;
}
if (k)
res.a[++res.len] = k;
res.del_zero();
return res;
}
template <typename JF>
inline friend GNUM operator-(GNUM x, JF y)
{
return x - GNUM(y);
}
inline friend GNUM operator-(GNUM x, GNUM y)
{
if (x < y)
putchar('-'), swap(x, y);
GNUM res = x;
register int cnt = x.len;
for (register int i = 1; i <= cnt; ++i)
{
res.a[i] -= y.a[i];
if (res.a[i] < 0)
--res.a[i + 1], res.a[i] += BASE;
}
res.del_zero();
return res;
}
template <typename CF>
inline friend GNUM operator*(const GNUM &x, const CF &y)
{
return x * GNUM(y);
}
inline friend GNUM operator*(const GNUM &x, const GNUM &y)
{
GNUM res;
res.len = x.len + y.len;
for (register int i = 1; i <= x.len; ++i)
{
for (register int j = 1; j <= y.len; ++j)
{
res.a[i + j - 1] += x.a[i] * y.a[j];
res.a[i + j] += res.a[i + j - 1] / BASE;
res.a[i + j - 1] %= BASE;
}
}
res.del_zero();
return res;
}
template <typename GF>
inline friend GNUM operator/(const GNUM &x, const GF &y)
{
GNUM res;
res.len = x.len;
long long k = 0;
for (register int i = x.len; i; --i)
{
k = k * BASE + x.a[i];
res.a[i] = k / y;
k %= y;
}
res.del_zero();
return res;
}
inline friend GNUM operator/(const GNUM &x, const GNUM &y)
{
GNUM res, k;
res.len = x.len;
for (register int i = x.len; i; --i)
{
k.add(x.a[i]);
while (k >= y)
k = k - y, res.a[i]++;
}
res.del_zero();
return res;
}
inline bool opd()
{
return a[1] & 1;
}
};
输出流
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