pandas之to_datetime时区转换

Posted 2020-11-29 zxpo

from datetime import date, datetime, timedelta

    import time

    import pandas as pd

    from pandas.tseries.offsets import Hour, Minute, Second

    

    

    print(time.localtime()) # time.struct_time(tm_year=2019, tm_mon=11, tm_mday=12, tm_hour=18, tm_min=34, tm_sec=52, tm_wday=1, tm_yday=316, tm_isdst=0)

    print(datetime.now().timestamp()) # 1573554892.416593 带小时分秒的

    print(datetime.now().tzinfo)    # None

    print(datetime.now().timetz())  # 18:34:52.416593

    print(datetime.now().date())    # 2019-11-12

    print(datetime.now())  # 2019-11-12 18:34:52.416593

        

    # date

    fixdate = date.today()+timedelta(days=-1)

    # date convert to datetime

    dtt = datetime(fixdate.year, fixdate.month, fixdate.day)

    print(dtt)              # 2019-11-11 00:00:00

    print(dtt.tzinfo)       # None 默认没有时区信息

    s_ts = dtt.timestamp()  # 1573401600.0 UTC时间戳

    print(‘------------------pd.to_datetime--------------------------‘)

    # pandas需要自己处理时区问题,默认没有时区信息，可以先本地化tz_localize时区再转换成tz_convert目标时区

    pddt = pd.to_datetime(s_ts, utc=True, unit=‘s‘) 

    print(pddt.tzinfo)                        # UTC

    print(pddt.timestamp())                   # 1573401600.0 

    print(pddt)                               # 2019-11-10 16:00:00+00:00

    pddt = pd.to_datetime(s_ts, utc=False, unit=‘s‘)

    print(pddt.tzinfo)                        # None

    print(pddt.timestamp())                   # 1573401600.0

    print(pddt)                               # 2019-11-10 16:00:00 

    pddt = pd.to_datetime(s_ts, utc=False, unit=‘s‘).tz_localize(‘Asia/Shanghai‘) # 本地化成某个时区

    print(pddt.tzinfo)                        # Asia/Shanghai

    print(pddt.timestamp())                   # 1573372800.0 

    print(pddt)                               # 2019-11-10 16:00:00+08:00 

    pddt = pd.to_datetime(s_ts, utc=True, unit=‘s‘).tz_convert(‘Asia/Shanghai‘)  # 转换成某个时区

    print(pddt.tzinfo)                        # Asia/Shanghai

    print(pddt.timestamp())                   # 1573401600.0 

    print(pddt)                               # 2019-11-11 00:00:00+08:00 

    print(‘--------------------Hour(23) + Minute(59) + Second(59) --------------------------‘)

    sec = Hour(23) + Minute(59) + Second(59) 

    print(sec.freqstr) # 86399S 秒，结束带个S

    pddt = pd.to_datetime(s_ts+int(sec.freqstr[:-1]), utc=True, unit=‘s‘).tz_convert(‘Asia/Shanghai‘)

    print(pddt)              # 2019-11-11 23:59:59+08:00

    print(pddt.timestamp())  # 1573487999.0 

    

     # 这样算本来才是真正想要的目标时间戳，推荐使用这种方式

    dtt_hms = (dtt + Hour(23) + Minute(59) + Second(59)).tz_localize(‘Asia/Shanghai‘).tz_convert(‘utc‘).value/1000000000

    print(dtt_hms)           # 1573487999.0 2019-11-11 23:59:59+08:00

    

    # 这样算出为是目标时间多了8小时的时间戳

    dtt_hms = (dtt + Hour(23) + Minute(59) + Second(59)).value/1000000000

    print(dtt_hms)           # 1573516799.0  2019-11-12 07:59:59 

    exit(0)