1050 String Subtraction

Posted ruruozhenhao

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了1050 String Subtraction相关的知识,希望对你有一定的参考价值。

Given two strings S?1?? and S?2??, S=S?1??−S?2?? is defined to be the remaining string after taking all the characters in S?2?? from S?1??. Your task is simply to calculate S?1??−S?2?? for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S?1?? and S?2??, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S?1??−S?2?? in one line.

Sample Input:

They are students.
aeiou
 

Sample Output:

Thy r stdnts.

题意:

  给出两个字符串,提出第一个字符串中,两个字符串都出现的字符。

思路:

  模拟。

Code:

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 
 5 int main() {
 6     string s1, s2;
 7     getline(cin, s1);
 8     getline(cin, s2);
 9     unordered_set<char> visited;
10     for (int i = 0; i < s2.length(); ++i) visited.insert(s2[i]);
11     string ans = "";
12     for (int i = 0; i < s1.length(); ++i)
13         if (visited.find(s1[i]) == visited.end()) ans += s1[i];
14     cout << ans << endl;
15     return 0;
16 }

 

以上是关于1050 String Subtraction的主要内容,如果未能解决你的问题,请参考以下文章

PAT甲级1050 String Subtraction (20 分)

PAT练习--1050 String Subtraction (20 分)

1050 String Subtraction

1050 String Subtraction

1050 String Subtraction (20 分)

1050. String Subtraction (20)