POJ:Arbitrage (搜索,汇率换算是否赚?)
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POJ 2240 http://poj.org/problem?id=2240
题意:判断是否存在使得汇率增多的环
【任意一个点的汇率增多都可以】
Floyd 简单变形
(w[i][j] = max(w[i][j], w[i][k]*w[k][j]))
#ifndef ONLINE_JUDGE
#pragma warning(disalbe : 4996)
#endif
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<string>
#include<map>
#include<cstring>
using namespace std;
const int maxn = 40;
double d[maxn];
int n, m;
double w[maxn][maxn];
map<string, int>mp;
void floyd() {
for (int k = 1; k <= n; ++k)
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= n; ++j)
w[i][j] = max(w[i][j], w[i][k] * w[k][j]);
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
#endif // !ONLINE_JUDGE
int kcase = 0;
while (cin >> n && n) {
mp.clear();
string s;
for (int i = 1; i <= n; ++i) {
cin >> s;
mp[s] = i;
w[i][i] = 1;//自己换自己
}
cin >> m;
string s1, s2;
double rat;
for (int i = 0; i < m; ++i) {
cin >> s1 >> rat >> s2;
w[mp[s1]][mp[s2]] = rat;
}
floyd();
bool flag = 0;
for (int i = 1; i <= n; ++i)
if (w[i][i] > 1.0) { flag = 1; break; }
printf("Case %d: ", ++kcase);
if (flag) printf("Yes
");
else printf("No
");
}
#ifndef ONLINE_JUDGE
fclose(stdin);
fclose(stdout);
system("out.txt");
#endif // !ONLINE_JUDGE
return 0;
}
bellman_ford 判断正环
#ifndef ONLINE_JUDGE
#pragma warning(disalbe : 4996)
#endif
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<string>
#include<map>
#include<cstring>
using namespace std;
const int maxn = 40;
double d[maxn];
int n, m;
struct Edge {
int u, v;
double r;
}edge[maxn * maxn];
map<string, int>mp;
bool bellman_ford(int s) {
memset(d, 0, sizeof(d));
d[s] = 1;
for(int i = 1;i <=n; ++i)
for (int j = 0; j < m; ++j) {
int u = edge[j].u;
int v = edge[j].v;
double r = edge[j].r;
if (d[v] < d[u] * r)
d[v] = d[u] * r;
}
if (d[s] > 1.0)return true;
return false;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
#endif // !ONLINE_JUDGE
int kcase = 0;
while (cin >> n && n) {
mp.clear();
string s;
for (int i = 1; i <= n; ++i) {
cin >> s;
mp[s] = i;
}
cin >> m;
string s1, s2;
double rat;
for (int i = 0; i < m; ++i) {
cin >> s1 >> rat >> s2;
edge[i].u = mp[s1];
edge[i].v = mp[s2];
edge[i].r = rat;
}
bool flag = false;
for(int i = 1;i <=n; ++i)
if (bellman_ford(i)) {
flag = true;
break;
}
printf("Case %d: ", ++kcase);
if (flag) printf("Yes
");
else printf("No
");
}
#ifndef ONLINE_JUDGE
fclose(stdin);
fclose(stdout);
system("out.txt");
#endif // !ONLINE_JUDGE
return 0;
}
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POJ - 2240 Arbitrage(Bellman-Ford)